3(x+4)=5(x-6)-32

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Solution for 3(x+4)=5(x-6)-32 equation: 



3(x+4)=5(x-6)-32

We move all terms to the left:

3(x+4)-(5(x-6)-32)=0

We multiply parentheses

3x-(5(x-6)-32)+12=0



We calculate terms in parentheses: -(5(x-6)-32), so:

5(x-6)-32

We multiply parentheses

5x-30-32

We add all the numbers together, and all the variables

5x-62

Back to the equation:

-(5x-62)



We get rid of parentheses

3x-5x+62+12=0

We add all the numbers together, and all the variables

-2x+74=0

We move all terms containing x to the left, all other terms to the right

-2x=-74

x=-74/-2

x=+37

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