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3(x+4)=7(2+x)-6
We move all terms to the left:
3(x+4)-(7(2+x)-6)=0
We add all the numbers together, and all the variables
3(x+4)-(7(x+2)-6)=0
We multiply parentheses
3x-(7(x+2)-6)+12=0
We calculate terms in parentheses: -(7(x+2)-6), so:We get rid of parentheses
7(x+2)-6
We multiply parentheses
7x+14-6
We add all the numbers together, and all the variables
7x+8
Back to the equation:
-(7x+8)
3x-7x-8+12=0
We add all the numbers together, and all the variables
-4x+4=0
We move all terms containing x to the left, all other terms to the right
-4x=-4
x=-4/-4
x=1
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