3(x+5)+(x-4)=22

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Solution for 3(x+5)+(x-4)=22 equation: 



3(x+5)+(x-4)=22

We move all terms to the left:

3(x+5)+(x-4)-(22)=0

We multiply parentheses

3x+(x-4)+15-22=0

We get rid of parentheses

3x+x-4+15-22=0

We add all the numbers together, and all the variables

4x-11=0

We move all terms containing x to the left, all other terms to the right

4x=11

x=11/4

x=2+3/4

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