3(x+5)+-2(x+2)=10

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Solution for 3(x+5)+-2(x+2)=10 equation: 



3(x+5)+-2(x+2)=10

We move all terms to the left:

3(x+5)+-2(x+2)-(10)=0

determiningTheFunctionDomain
3(x+5)-2(x+2)-10+=0

We add all the numbers together, and all the variables

3(x+5)-2(x+2)=0

We multiply parentheses

3x-2x+15-4=0

We add all the numbers together, and all the variables

x+11=0

We move all terms containing x to the left, all other terms to the right

x=-11

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