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3(x+5)+1=5(x+2)
We move all terms to the left:
3(x+5)+1-(5(x+2))=0
We multiply parentheses
3x-(5(x+2))+15+1=0
We calculate terms in parentheses: -(5(x+2)), so:We add all the numbers together, and all the variables
5(x+2)
We multiply parentheses
5x+10
Back to the equation:
-(5x+10)
3x-(5x+10)+16=0
We get rid of parentheses
3x-5x-10+16=0
We add all the numbers together, and all the variables
-2x+6=0
We move all terms containing x to the left, all other terms to the right
-2x=-6
x=-6/-2
x=+3
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