3(x+5)+20=2(x+4)

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Solution for 3(x+5)+20=2(x+4) equation:



3(x+5)+20=2(x+4)
We move all terms to the left:
3(x+5)+20-(2(x+4))=0
We multiply parentheses
3x-(2(x+4))+15+20=0
We calculate terms in parentheses: -(2(x+4)), so:
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
We add all the numbers together, and all the variables
3x-(2x+8)+35=0
We get rid of parentheses
3x-2x-8+35=0
We add all the numbers together, and all the variables
x+27=0
We move all terms containing x to the left, all other terms to the right
x=-27

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