3(x+5)+20=2(x+4)

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Solution for 3(x+5)+20=2(x+4) equation: 



3(x+5)+20=2(x+4)

We move all terms to the left:

3(x+5)+20-(2(x+4))=0

We multiply parentheses

3x-(2(x+4))+15+20=0



We calculate terms in parentheses: -(2(x+4)), so:

2(x+4)

We multiply parentheses

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

3x-(2x+8)+35=0

We get rid of parentheses

3x-2x-8+35=0

We add all the numbers together, and all the variables

x+27=0

We move all terms containing x to the left, all other terms to the right

x=-27

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