3(x+5)+3x+1=32

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Solution for 3(x+5)+3x+1=32 equation:



3(x+5)+3x+1=32
We move all terms to the left:
3(x+5)+3x+1-(32)=0
We add all the numbers together, and all the variables
3x+3(x+5)-31=0
We multiply parentheses
3x+3x+15-31=0
We add all the numbers together, and all the variables
6x-16=0
We move all terms containing x to the left, all other terms to the right
6x=16
x=16/6
x=2+2/3

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