3(x+5)+4(x+2)=21

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Solution for 3(x+5)+4(x+2)=21 equation: 


Simplifying
3(x + 5) + 4(x + 2) = 21

Reorder the terms:
3(5 + x) + 4(x + 2) = 21
(5 * 3 + x * 3) + 4(x + 2) = 21
(15 + 3x) + 4(x + 2) = 21

Reorder the terms:
15 + 3x + 4(2 + x) = 21
15 + 3x + (2 * 4 + x * 4) = 21
15 + 3x + (8 + 4x) = 21

Reorder the terms:
15 + 8 + 3x + 4x = 21

Combine like terms: 15 + 8 = 23
23 + 3x + 4x = 21

Combine like terms: 3x + 4x = 7x
23 + 7x = 21

Solving
23 + 7x = 21

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-23' to each side of the equation.
23 + -23 + 7x = 21 + -23

Combine like terms: 23 + -23 = 0
0 + 7x = 21 + -23
7x = 21 + -23

Combine like terms: 21 + -23 = -2
7x = -2

Divide each side by '7'.
x = -0.2857142857

Simplifying
x = -0.2857142857

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