3(x+5)+42=8x-13

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Solution for 3(x+5)+42=8x-13 equation: 



3(x+5)+42=8x-13

We move all terms to the left:

3(x+5)+42-(8x-13)=0

We multiply parentheses

3x-(8x-13)+15+42=0

We get rid of parentheses

3x-8x+13+15+42=0

We add all the numbers together, and all the variables

-5x+70=0

We move all terms containing x to the left, all other terms to the right

-5x=-70

x=-70/-5

x=+14

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