3(x+5)+7(x-1)-8(2x-15)=x/2

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Solution for 3(x+5)+7(x-1)-8(2x-15)=x/2 equation: 



3(x+5)+7(x-1)-8(2x-15)=x/2

We move all terms to the left:

3(x+5)+7(x-1)-8(2x-15)-(x/2)=0

We add all the numbers together, and all the variables

3(x+5)+7(x-1)-8(2x-15)-(+x/2)=0

We multiply parentheses

3x+7x-16x-(+x/2)+15-7+120=0

We get rid of parentheses

3x+7x-16x-x/2+15-7+120=0

We multiply all the terms by the denominator


3x*2+7x*2-16x*2-x+15*2-7*2+120*2=0

We add all the numbers together, and all the variables

-1x+3x*2+7x*2-16x*2+256=0

Wy multiply elements

-1x+6x+14x-32x+256=0

We add all the numbers together, and all the variables

-13x+256=0

We move all terms containing x to the left, all other terms to the right

-13x=-256

x=-256/-13

x=19+9/13

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