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3(x+5)+7x=5(x+1)+15
We move all terms to the left:
3(x+5)+7x-(5(x+1)+15)=0
We add all the numbers together, and all the variables
7x+3(x+5)-(5(x+1)+15)=0
We multiply parentheses
7x+3x-(5(x+1)+15)+15=0
We calculate terms in parentheses: -(5(x+1)+15), so:We add all the numbers together, and all the variables
5(x+1)+15
We multiply parentheses
5x+5+15
We add all the numbers together, and all the variables
5x+20
Back to the equation:
-(5x+20)
10x-(5x+20)+15=0
We get rid of parentheses
10x-5x-20+15=0
We add all the numbers together, and all the variables
5x-5=0
We move all terms containing x to the left, all other terms to the right
5x=5
x=5/5
x=1
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