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3(x+5)+9x=(3x+15)+9x
We move all terms to the left:
3(x+5)+9x-((3x+15)+9x)=0
We add all the numbers together, and all the variables
9x+3(x+5)-((3x+15)+9x)=0
We multiply parentheses
9x+3x-((3x+15)+9x)+15=0
We calculate terms in parentheses: -((3x+15)+9x), so:We add all the numbers together, and all the variables
(3x+15)+9x
We add all the numbers together, and all the variables
9x+(3x+15)
We get rid of parentheses
9x+3x+15
We add all the numbers together, and all the variables
12x+15
Back to the equation:
-(12x+15)
12x-(12x+15)+15=0
We get rid of parentheses
12x-12x-15+15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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