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3(x+5)+x=2(2x+4)-3
We move all terms to the left:
3(x+5)+x-(2(2x+4)-3)=0
We add all the numbers together, and all the variables
x+3(x+5)-(2(2x+4)-3)=0
We multiply parentheses
x+3x-(2(2x+4)-3)+15=0
We calculate terms in parentheses: -(2(2x+4)-3), so:We add all the numbers together, and all the variables
2(2x+4)-3
We multiply parentheses
4x+8-3
We add all the numbers together, and all the variables
4x+5
Back to the equation:
-(4x+5)
4x-(4x+5)+15=0
We get rid of parentheses
4x-4x-5+15=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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