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3(x+5)-25=9+2(x+7)
We move all terms to the left:
3(x+5)-25-(9+2(x+7))=0
We multiply parentheses
3x-(9+2(x+7))+15-25=0
We calculate terms in parentheses: -(9+2(x+7)), so:We add all the numbers together, and all the variables
9+2(x+7)
determiningTheFunctionDomain 2(x+7)+9
We multiply parentheses
2x+14+9
We add all the numbers together, and all the variables
2x+23
Back to the equation:
-(2x+23)
3x-(2x+23)-10=0
We get rid of parentheses
3x-2x-23-10=0
We add all the numbers together, and all the variables
x-33=0
We move all terms containing x to the left, all other terms to the right
x=33
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