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3(x+5)-2=-2(x-8)+3
We move all terms to the left:
3(x+5)-2-(-2(x-8)+3)=0
We multiply parentheses
3x-(-2(x-8)+3)+15-2=0
We calculate terms in parentheses: -(-2(x-8)+3), so:We add all the numbers together, and all the variables
-2(x-8)+3
We multiply parentheses
-2x+16+3
We add all the numbers together, and all the variables
-2x+19
Back to the equation:
-(-2x+19)
3x-(-2x+19)+13=0
We get rid of parentheses
3x+2x-19+13=0
We add all the numbers together, and all the variables
5x-6=0
We move all terms containing x to the left, all other terms to the right
5x=6
x=6/5
x=1+1/5
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