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3(x+5)-2=6x-3(-5+x)
We move all terms to the left:
3(x+5)-2-(6x-3(-5+x))=0
We add all the numbers together, and all the variables
3(x+5)-(6x-3(x-5))-2=0
We multiply parentheses
3x-(6x-3(x-5))+15-2=0
We calculate terms in parentheses: -(6x-3(x-5)), so:We add all the numbers together, and all the variables
6x-3(x-5)
We multiply parentheses
6x-3x+15
We add all the numbers together, and all the variables
3x+15
Back to the equation:
-(3x+15)
3x-(3x+15)+13=0
We get rid of parentheses
3x-3x-15+13=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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