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3(x+5)-3=32-2x
We move all terms to the left:
3(x+5)-3-(32-2x)=0
We add all the numbers together, and all the variables
3(x+5)-(-2x+32)-3=0
We multiply parentheses
3x-(-2x+32)+15-3=0
We get rid of parentheses
3x+2x-32+15-3=0
We add all the numbers together, and all the variables
5x-20=0
We move all terms containing x to the left, all other terms to the right
5x=20
x=20/5
x=4
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