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3(x+5)-3=4(3x+2)-7x
We move all terms to the left:
3(x+5)-3-(4(3x+2)-7x)=0
We multiply parentheses
3x-(4(3x+2)-7x)+15-3=0
We calculate terms in parentheses: -(4(3x+2)-7x), so:We add all the numbers together, and all the variables
4(3x+2)-7x
We add all the numbers together, and all the variables
-7x+4(3x+2)
We multiply parentheses
-7x+12x+8
We add all the numbers together, and all the variables
5x+8
Back to the equation:
-(5x+8)
3x-(5x+8)+12=0
We get rid of parentheses
3x-5x-8+12=0
We add all the numbers together, and all the variables
-2x+4=0
We move all terms containing x to the left, all other terms to the right
-2x=-4
x=-4/-2
x=+2
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