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3(x+5)-4=2(2x-1)
We move all terms to the left:
3(x+5)-4-(2(2x-1))=0
We multiply parentheses
3x-(2(2x-1))+15-4=0
We calculate terms in parentheses: -(2(2x-1)), so:We add all the numbers together, and all the variables
2(2x-1)
We multiply parentheses
4x-2
Back to the equation:
-(4x-2)
3x-(4x-2)+11=0
We get rid of parentheses
3x-4x+2+11=0
We add all the numbers together, and all the variables
-1x+13=0
We move all terms containing x to the left, all other terms to the right
-x=-13
x=-13/-1
x=+13
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