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3(x+5)-4x=6x-4(2x-5)
We move all terms to the left:
3(x+5)-4x-(6x-4(2x-5))=0
We add all the numbers together, and all the variables
-4x+3(x+5)-(6x-4(2x-5))=0
We multiply parentheses
-4x+3x-(6x-4(2x-5))+15=0
We calculate terms in parentheses: -(6x-4(2x-5)), so:We add all the numbers together, and all the variables
6x-4(2x-5)
We multiply parentheses
6x-8x+20
We add all the numbers together, and all the variables
-2x+20
Back to the equation:
-(-2x+20)
-1x-(-2x+20)+15=0
We get rid of parentheses
-1x+2x-20+15=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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