3(x+5)-7=(x+2)

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Solution for 3(x+5)-7=(x+2) equation: 



3(x+5)-7=(x+2)

We move all terms to the left:

3(x+5)-7-((x+2))=0

We multiply parentheses

3x-((x+2))+15-7=0



We calculate terms in parentheses: -((x+2)), so:

(x+2)

We get rid of parentheses

x+2

Back to the equation:

-(x+2)



We add all the numbers together, and all the variables

3x-(x+2)+8=0

We get rid of parentheses

3x-x-2+8=0

We add all the numbers together, and all the variables

2x+6=0

We move all terms containing x to the left, all other terms to the right

2x=-6

x=-6/2

x=-3

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