3(x+5)-7x=2(x+3)+6x

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Solution for 3(x+5)-7x=2(x+3)+6x equation: 



3(x+5)-7x=2(x+3)+6x

We move all terms to the left:

3(x+5)-7x-(2(x+3)+6x)=0

We add all the numbers together, and all the variables

-7x+3(x+5)-(2(x+3)+6x)=0

We multiply parentheses

-7x+3x-(2(x+3)+6x)+15=0



We calculate terms in parentheses: -(2(x+3)+6x), so:

2(x+3)+6x

We add all the numbers together, and all the variables

6x+2(x+3)

We multiply parentheses

6x+2x+6

We add all the numbers together, and all the variables

8x+6

Back to the equation:

-(8x+6)



We add all the numbers together, and all the variables

-4x-(8x+6)+15=0

We get rid of parentheses

-4x-8x-6+15=0

We add all the numbers together, and all the variables

-12x+9=0

We move all terms containing x to the left, all other terms to the right

-12x=-9

x=-9/-12

x=3/4

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