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3(x+5)-9=2(x+4)-2+x
We move all terms to the left:
3(x+5)-9-(2(x+4)-2+x)=0
We multiply parentheses
3x-(2(x+4)-2+x)+15-9=0
We calculate terms in parentheses: -(2(x+4)-2+x), so:We add all the numbers together, and all the variables
2(x+4)-2+x
determiningTheFunctionDomain 2(x+4)+x-2
We add all the numbers together, and all the variables
x+2(x+4)-2
We multiply parentheses
x+2x+8-2
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
3x-(3x+6)+6=0
We get rid of parentheses
3x-3x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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