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3(x+5)14x=5(3x+1)-11x
We move all terms to the left:
3(x+5)14x-(5(3x+1)-11x)=0
We multiply parentheses
42x^2+210x-(5(3x+1)-11x)=0
We calculate terms in parentheses: -(5(3x+1)-11x), so:We get rid of parentheses
5(3x+1)-11x
We add all the numbers together, and all the variables
-11x+5(3x+1)
We multiply parentheses
-11x+15x+5
We add all the numbers together, and all the variables
4x+5
Back to the equation:
-(4x+5)
42x^2+210x-4x-5=0
We add all the numbers together, and all the variables
42x^2+206x-5=0
a = 42; b = 206; c = -5;
Δ = b2-4ac
Δ = 2062-4·42·(-5)
Δ = 43276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{43276}=\sqrt{4*10819}=\sqrt{4}*\sqrt{10819}=2\sqrt{10819}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(206)-2\sqrt{10819}}{2*42}=\frac{-206-2\sqrt{10819}}{84} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(206)+2\sqrt{10819}}{2*42}=\frac{-206+2\sqrt{10819}}{84} $
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