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3(x+5)=-2-3(x+1)
We move all terms to the left:
3(x+5)-(-2-3(x+1))=0
We multiply parentheses
3x-(-2-3(x+1))+15=0
We calculate terms in parentheses: -(-2-3(x+1)), so:We get rid of parentheses
-2-3(x+1)
determiningTheFunctionDomain -3(x+1)-2
We multiply parentheses
-3x-3-2
We add all the numbers together, and all the variables
-3x-5
Back to the equation:
-(-3x-5)
3x+3x+5+15=0
We add all the numbers together, and all the variables
6x+20=0
We move all terms containing x to the left, all other terms to the right
6x=-20
x=-20/6
x=-3+1/3
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