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3(x+5)=2/5x-15
We move all terms to the left:
3(x+5)-(2/5x-15)=0
Domain of the equation: 5x-15)!=0We multiply parentheses
x∈R
3x-(2/5x-15)+15=0
We get rid of parentheses
3x-2/5x+15+15=0
We multiply all the terms by the denominator
3x*5x+15*5x+15*5x-2=0
Wy multiply elements
15x^2+75x+75x-2=0
We add all the numbers together, and all the variables
15x^2+150x-2=0
a = 15; b = 150; c = -2;
Δ = b2-4ac
Δ = 1502-4·15·(-2)
Δ = 22620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{22620}=\sqrt{4*5655}=\sqrt{4}*\sqrt{5655}=2\sqrt{5655}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-2\sqrt{5655}}{2*15}=\frac{-150-2\sqrt{5655}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+2\sqrt{5655}}{2*15}=\frac{-150+2\sqrt{5655}}{30} $
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