3(x+5)=21+-4(2x-5)

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Solution for 3(x+5)=21+-4(2x-5) equation: 



3(x+5)=21+-4(2x-5)

We move all terms to the left:

3(x+5)-(21+-4(2x-5))=0

We use the square of the difference formula

3(x+5)-(21-4(2x-5))=0

We multiply parentheses

3x-(21-4(2x-5))+15=0



We calculate terms in parentheses: -(21-4(2x-5)), so:

21-4(2x-5)

determiningTheFunctionDomain
-4(2x-5)+21

We multiply parentheses

-8x+20+21

We add all the numbers together, and all the variables

-8x+41

Back to the equation:

-(-8x+41)



We get rid of parentheses

3x+8x-41+15=0

We add all the numbers together, and all the variables

11x-26=0

We move all terms containing x to the left, all other terms to the right

11x=26

x=26/11

x=2+4/11

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