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3(x+5)=22(3x+12)
We move all terms to the left:
3(x+5)-(22(3x+12))=0
We multiply parentheses
3x-(22(3x+12))+15=0
We calculate terms in parentheses: -(22(3x+12)), so:We get rid of parentheses
22(3x+12)
We multiply parentheses
66x+264
Back to the equation:
-(66x+264)
3x-66x-264+15=0
We add all the numbers together, and all the variables
-63x-249=0
We move all terms containing x to the left, all other terms to the right
-63x=249
x=249/-63
x=-3+20/21
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