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3(x+5)=4(3x-5)
We move all terms to the left:
3(x+5)-(4(3x-5))=0
We multiply parentheses
3x-(4(3x-5))+15=0
We calculate terms in parentheses: -(4(3x-5)), so:We get rid of parentheses
4(3x-5)
We multiply parentheses
12x-20
Back to the equation:
-(12x-20)
3x-12x+20+15=0
We add all the numbers together, and all the variables
-9x+35=0
We move all terms containing x to the left, all other terms to the right
-9x=-35
x=-35/-9
x=3+8/9
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