3(x+5)=4(x+-2)

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Solution for 3(x+5)=4(x+-2) equation: 



3(x+5)=4(x+-2)

We move all terms to the left:

3(x+5)-(4(x+-2))=0

We add all the numbers together, and all the variables

3(x+5)-(4(x-2))=0

We multiply parentheses

3x-(4(x-2))+15=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

3x-4x+8+15=0

We add all the numbers together, and all the variables

-1x+23=0

We move all terms containing x to the left, all other terms to the right

-x=-23

x=-23/-1

x=+23

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