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3(x+5)=5(2x-6)=3
We move all terms to the left:
3(x+5)-(5(2x-6))=0
We multiply parentheses
3x-(5(2x-6))+15=0
We calculate terms in parentheses: -(5(2x-6)), so:We get rid of parentheses
5(2x-6)
We multiply parentheses
10x-30
Back to the equation:
-(10x-30)
3x-10x+30+15=0
We add all the numbers together, and all the variables
-7x+45=0
We move all terms containing x to the left, all other terms to the right
-7x=-45
x=-45/-7
x=6+3/7
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