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3(x+5)=5(2x-6+4)
We move all terms to the left:
3(x+5)-(5(2x-6+4))=0
We add all the numbers together, and all the variables
3(x+5)-(5(2x-2))=0
We multiply parentheses
3x-(5(2x-2))+15=0
We calculate terms in parentheses: -(5(2x-2)), so:We get rid of parentheses
5(2x-2)
We multiply parentheses
10x-10
Back to the equation:
-(10x-10)
3x-10x+10+15=0
We add all the numbers together, and all the variables
-7x+25=0
We move all terms containing x to the left, all other terms to the right
-7x=-25
x=-25/-7
x=3+4/7
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