3(x+5)=6(x-2)+6

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Solution for 3(x+5)=6(x-2)+6 equation: 



3(x+5)=6(x-2)+6

We move all terms to the left:

3(x+5)-(6(x-2)+6)=0

We multiply parentheses

3x-(6(x-2)+6)+15=0



We calculate terms in parentheses: -(6(x-2)+6), so:

6(x-2)+6

We multiply parentheses

6x-12+6

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

3x-6x+6+15=0

We add all the numbers together, and all the variables

-3x+21=0

We move all terms containing x to the left, all other terms to the right

-3x=-21

x=-21/-3

x=+7

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