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3(x+5)=6-2(3x-6)
We move all terms to the left:
3(x+5)-(6-2(3x-6))=0
We multiply parentheses
3x-(6-2(3x-6))+15=0
We calculate terms in parentheses: -(6-2(3x-6)), so:We get rid of parentheses
6-2(3x-6)
determiningTheFunctionDomain -2(3x-6)+6
We multiply parentheses
-6x+12+6
We add all the numbers together, and all the variables
-6x+18
Back to the equation:
-(-6x+18)
3x+6x-18+15=0
We add all the numbers together, and all the variables
9x-3=0
We move all terms containing x to the left, all other terms to the right
9x=3
x=3/9
x=1/3
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