3(x+5)=7(x+2)+5

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Solution for 3(x+5)=7(x+2)+5 equation: 



3(x+5)=7(x+2)+5

We move all terms to the left:

3(x+5)-(7(x+2)+5)=0

We multiply parentheses

3x-(7(x+2)+5)+15=0



We calculate terms in parentheses: -(7(x+2)+5), so:

7(x+2)+5

We multiply parentheses

7x+14+5

We add all the numbers together, and all the variables

7x+19

Back to the equation:

-(7x+19)



We get rid of parentheses

3x-7x-19+15=0

We add all the numbers together, and all the variables

-4x-4=0

We move all terms containing x to the left, all other terms to the right

-4x=4

x=4/-4

x=-1

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