3(x+5)=8x-4(x-1)

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Solution for 3(x+5)=8x-4(x-1) equation: 



3(x+5)=8x-4(x-1)

We move all terms to the left:

3(x+5)-(8x-4(x-1))=0

We multiply parentheses

3x-(8x-4(x-1))+15=0



We calculate terms in parentheses: -(8x-4(x-1)), so:

8x-4(x-1)

We multiply parentheses

8x-4x+4

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

3x-4x-4+15=0

We add all the numbers together, and all the variables

-1x+11=0

We move all terms containing x to the left, all other terms to the right

-x=-11

x=-11/-1

x=+11

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