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3(x+8)(x-2)=0
We multiply parentheses ..
3(+x^2-2x+8x-16)=0
We multiply parentheses
3x^2-6x+24x-48=0
We add all the numbers together, and all the variables
3x^2+18x-48=0
a = 3; b = 18; c = -48;
Δ = b2-4ac
Δ = 182-4·3·(-48)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-30}{2*3}=\frac{-48}{6} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+30}{2*3}=\frac{12}{6} =2 $
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