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3*(x+8) = 2*((3/2)*x+10) // - 2*((3/2)*x+10)
3*(x+8)-(2*((3/2)*x+10)) = 0
3*(x+8)-2*((3/2)*x+10) = 0
3*(x+8)-2*(3/2*x+10) = 0
3*(x+8)-2*(3/2*x+10) = 0
4 = 0
4 = 0
x belongs to the empty set
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