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3(x+9)+3=2(x-5)+10
We move all terms to the left:
3(x+9)+3-(2(x-5)+10)=0
We multiply parentheses
3x-(2(x-5)+10)+27+3=0
We calculate terms in parentheses: -(2(x-5)+10), so:We add all the numbers together, and all the variables
2(x-5)+10
We multiply parentheses
2x-10+10
We add all the numbers together, and all the variables
2x
Back to the equation:
-(2x)
x+30=0
We move all terms containing x to the left, all other terms to the right
x=-30
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