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3(x+9)=2(x-4)
We move all terms to the left:
3(x+9)-(2(x-4))=0
We multiply parentheses
3x-(2(x-4))+27=0
We calculate terms in parentheses: -(2(x-4)), so:We get rid of parentheses
2(x-4)
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
3x-2x+8+27=0
We add all the numbers together, and all the variables
x+35=0
We move all terms containing x to the left, all other terms to the right
x=-35
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