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3(x+9+3)=2(2x-4+2)
We move all terms to the left:
3(x+9+3)-(2(2x-4+2))=0
We add all the numbers together, and all the variables
3(x+12)-(2(2x-2))=0
We multiply parentheses
3x-(2(2x-2))+36=0
We calculate terms in parentheses: -(2(2x-2)), so:We get rid of parentheses
2(2x-2)
We multiply parentheses
4x-4
Back to the equation:
-(4x-4)
3x-4x+4+36=0
We add all the numbers together, and all the variables
-1x+40=0
We move all terms containing x to the left, all other terms to the right
-x=-40
x=-40/-1
x=+40
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