3(x+y)-2z+4y/2

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Solution for 3(x+y)-2z+4y/2 equation: 


x in (-oo:+oo)

3*(x+y)+(4*y)/2-(2*z) = 0

3*(x+y)+(4*y)/2-2*z = 0

3*(x+y)+2*y-2*z = 0

3*(x+y)+2*y-2*z = 0

3*x+5*y-2*z = 0

3*x+5*y-2*z = 0

3*x+5*y-2*z = 0 // - 5*y-2*z

3*x = -(5*y-2*z) // : 3

x = (-(5*y-2*z))/3

x = (-(5*y-2*z))/3

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