3(x+y)=3x+3y

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Solution for 3(x+y)=3x+3y equation:


Simplifying
3(x + y) = 3x + 3y
(x * 3 + y * 3) = 3x + 3y
(3x + 3y) = 3x + 3y

Add '-3x' to each side of the equation.
3x + -3x + 3y = 3x + -3x + 3y

Combine like terms: 3x + -3x = 0
0 + 3y = 3x + -3x + 3y
3y = 3x + -3x + 3y

Combine like terms: 3x + -3x = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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