3(x+y)=7(y+1)+3

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Solution for 3(x+y)=7(y+1)+3 equation:


Simplifying
3(x + y) = 7(y + 1) + 3
(x * 3 + y * 3) = 7(y + 1) + 3
(3x + 3y) = 7(y + 1) + 3

Reorder the terms:
3x + 3y = 7(1 + y) + 3
3x + 3y = (1 * 7 + y * 7) + 3
3x + 3y = (7 + 7y) + 3

Reorder the terms:
3x + 3y = 7 + 3 + 7y

Combine like terms: 7 + 3 = 10
3x + 3y = 10 + 7y

Solving
3x + 3y = 10 + 7y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3y' to each side of the equation.
3x + 3y + -3y = 10 + 7y + -3y

Combine like terms: 3y + -3y = 0
3x + 0 = 10 + 7y + -3y
3x = 10 + 7y + -3y

Combine like terms: 7y + -3y = 4y
3x = 10 + 4y

Divide each side by '3'.
x = 3.333333333 + 1.333333333y

Simplifying
x = 3.333333333 + 1.333333333y

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