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3(x-(6-3x)+5)=11x+8
We move all terms to the left:
3(x-(6-3x)+5)-(11x+8)=0
We add all the numbers together, and all the variables
3(x-(-3x+6)+5)-(11x+8)=0
We get rid of parentheses
3(x-(-3x+6)+5)-11x-8=0
We add all the numbers together, and all the variables
-11x+3(x-(-3x+6)+5)-8=0
We move all terms containing x to the left, all other terms to the right
-11x+3(x-(-3x+6)+5)=8
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