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3(x-1)(5x+4)=0
We multiply parentheses ..
3(+5x^2+4x-5x-4)=0
We multiply parentheses
15x^2+12x-15x-12=0
We add all the numbers together, and all the variables
15x^2-3x-12=0
a = 15; b = -3; c = -12;
Δ = b2-4ac
Δ = -32-4·15·(-12)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-27}{2*15}=\frac{-24}{30} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+27}{2*15}=\frac{30}{30} =1 $
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