3(x-1)(x+1)=3x-6

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Solution for 3(x-1)(x+1)=3x-6 equation:


Simplifying
3(x + -1)(x + 1) = 3x + -6

Reorder the terms:
3(-1 + x)(x + 1) = 3x + -6

Reorder the terms:
3(-1 + x)(1 + x) = 3x + -6

Multiply (-1 + x) * (1 + x)
3(-1(1 + x) + x(1 + x)) = 3x + -6
3((1 * -1 + x * -1) + x(1 + x)) = 3x + -6
3((-1 + -1x) + x(1 + x)) = 3x + -6
3(-1 + -1x + (1 * x + x * x)) = 3x + -6
3(-1 + -1x + (1x + x2)) = 3x + -6

Combine like terms: -1x + 1x = 0
3(-1 + 0 + x2) = 3x + -6
3(-1 + x2) = 3x + -6
(-1 * 3 + x2 * 3) = 3x + -6
(-3 + 3x2) = 3x + -6

Reorder the terms:
-3 + 3x2 = -6 + 3x

Solving
-3 + 3x2 = -6 + 3x

Solving for variable 'x'.

Reorder the terms:
-3 + 6 + -3x + 3x2 = -6 + 3x + 6 + -3x

Combine like terms: -3 + 6 = 3
3 + -3x + 3x2 = -6 + 3x + 6 + -3x

Reorder the terms:
3 + -3x + 3x2 = -6 + 6 + 3x + -3x

Combine like terms: -6 + 6 = 0
3 + -3x + 3x2 = 0 + 3x + -3x
3 + -3x + 3x2 = 3x + -3x

Combine like terms: 3x + -3x = 0
3 + -3x + 3x2 = 0

Factor out the Greatest Common Factor (GCF), '3'.
3(1 + -1x + x2) = 0

Ignore the factor 3.

Subproblem 1

Set the factor '(1 + -1x + x2)' equal to zero and attempt to solve: Simplifying 1 + -1x + x2 = 0 Solving 1 + -1x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '-1' to each side of the equation. 1 + -1x + -1 + x2 = 0 + -1 Reorder the terms: 1 + -1 + -1x + x2 = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x + x2 = 0 + -1 -1x + x2 = 0 + -1 Combine like terms: 0 + -1 = -1 -1x + x2 = -1 The x term is -1x. Take half its coefficient (-0.5). Square it (0.25) and add it to both sides. Add '0.25' to each side of the equation. -1x + 0.25 + x2 = -1 + 0.25 Reorder the terms: 0.25 + -1x + x2 = -1 + 0.25 Combine like terms: -1 + 0.25 = -0.75 0.25 + -1x + x2 = -0.75 Factor a perfect square on the left side: (x + -0.5)(x + -0.5) = -0.75 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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