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3(x-1)+(2(3-2x)=6(x+4)
We move all terms to the left:
3(x-1)+(2(3-2x)-(6(x+4))=0
We add all the numbers together, and all the variables
3(x-1)+(2(-2x+3)-(6(x+4))=0
We multiply parentheses
3x+(2(-2x+3)-(6(x+4))-3=0
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