3(x-1)+(3x+12)=25+x

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Solution for 3(x-1)+(3x+12)=25+x equation: 



3(x-1)+(3x+12)=25+x

We move all terms to the left:

3(x-1)+(3x+12)-(25+x)=0

We add all the numbers together, and all the variables

3(x-1)+(3x+12)-(x+25)=0

We multiply parentheses

3x+(3x+12)-(x+25)-3=0

We get rid of parentheses

3x+3x-x+12-25-3=0

We add all the numbers together, and all the variables

5x-16=0

We move all terms containing x to the left, all other terms to the right

5x=16

x=16/5

x=3+1/5

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