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3(x-1)+12=2(x+4)
We move all terms to the left:
3(x-1)+12-(2(x+4))=0
We multiply parentheses
3x-(2(x+4))-3+12=0
We calculate terms in parentheses: -(2(x+4)), so:We add all the numbers together, and all the variables
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
3x-(2x+8)+9=0
We get rid of parentheses
3x-2x-8+9=0
We add all the numbers together, and all the variables
x+1=0
We move all terms containing x to the left, all other terms to the right
x=-1
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